php 级联菜单,php级联菜单不用ajax如何实现
不是很明确你的意思,是要实现这样无限级树形菜单么?/*li {list-style-type:none;}*/span{cursor: pointer;background-color: yellowgreen;font-size: 20px}.hidden{display: none}$arr = Array(Array("cat_id" => 3, "cat_name" => "J
不是很明确你的意思,是要实现这样无限级树形菜单么?
/*li {list-style-type:none;}*/
span{cursor: pointer;background-color: yellowgreen;font-size: 20px}
.hidden{display: none}
$arr = Array(
Array("cat_id" => 3, "cat_name" => "JavaScript", "parent_id" => 0, "level" => 0),
Array("cat_id" => 5, "cat_name" => "Jquery", "parent_id" => 3, "level" => 1),
Array("cat_id" => 6, "cat_name" => "JS高级", "parent_id" => 3, "level" => 1),
Array("cat_id" => 7, "cat_name" => "JS高级更高级1", "parent_id" => 6, "level" => 3),
Array("cat_id" => 8, "cat_name" => "JS高级更高级2", "parent_id" => 6, "level" => 3),
Array("cat_id" => 9, "cat_name" => "JS高级更高级3", "parent_id" => 6, "level" => 3),
Array("cat_id" => 4, "cat_name" => "PHP", "parent_id" => 0, "level" => 0),
Array("cat_id" => 10, "cat_name" => "PHP高级1", "parent_id" => 4, "level" => 0),
Array("cat_id" => 12, "cat_name" => "PHP高级2", "parent_id" => 4, "level" => 0),
Array("cat_id" => 13, "cat_name" => "PHP高级3", "parent_id" => 4, "level" => 0)
);
//创建树形菜单
function createTree(&$arr, $parent_id) {
$hide = "";
if ($parent_id != 0) {
$hide = "hidden";
}
$funcName = __FUNCTION__;
$ul = "";
$li = "";
for ($i = 0; $i < count($arr); $i++) {
if ($arr[$i]["parent_id"] == $parent_id) {
$child = $funcName($arr, $arr[$i]['cat_id']);
$li .= "\r\n
{$arr[$i]["cat_name"]}{$child}\r\n";}
}
if ($li != "") {
$ul = "
- {$li}
";
}
return $ul;
}
echo createTree($arr, 0);
?>
(function() {
$(".cate").hover(function() {
$(this).children("ul").show()
}, function() {
$(this).children("ul").hide()
})
})()
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