List[List[str]]-＞List[List[int, int, List[str], array, List[bool]]-----一个具体例子（有碰到这样的题要求定义函数，不让用eval）

row = ['0', '1', 'NDP;Liberal;Green;CPC', '1;4;2;3', 'NO;YES;NO;NO']转换成'''SAMPLE_DATA_1 = [[0, 1, ['NDP', 'LIBERAL', 'GREEN', 'CPC'], [1, 4, 2, 3],[False, True, False, False]],[1, 2, ['LIBERAL', 'NDP'

晨打水水水

1061人浏览 · 2021-11-11 14:10:15

晨打水水水 · 2021-11-11 14:10:15 发布

row = ['0', '1', 'NDP;LIBERAL;GREEN;CPC', '1;4;2;3', 'NO;YES;NO;NO']

转换成

'''SAMPLE_DATA_1 = [[0, 1, ['NDP', 'LIBERAL', 'GREEN', 'CPC'], [1, 4, 2, 3],
                  [False, True, False, False]],
                 [1, 2, ['LIBERAL', 'NDP', 'GREEN', 'CPC'], [2, 1, 4, 2],
                  [False, False, True, True]],
                 [1, 3, ['GREEN', 'NDP', 'CPC', 'LIBERAL'], [1, 5, 1, 2],
                  [False, True, False, True]],
                 [1, 4, ['CPC', 'LIBERAL', 'NDP', 'GREEN'], [5, 0, 3, 2], 
                  [True, False, True, True]]]
'''
SAMPLE_DATA_1[0]

定义一个函数，然后输入clean_data([row])

[注]一定是[row]，不是row，因为row只是List[str]

def clean_data(data: List[List[str]]) -> None:
    for l in data:
        l[0] = int(l[0])
        l[1] = int(l[1])
        l[2] = l[2].split(';')
        l[3] = l[3].split(';')
        m = []
        for s in l[3]:
            m.append(int(s))
        l[3] = m
        l[4] = l[4].split(';')
        k = []
        for s in l[4]:
            if s == 'NO':
                s = 0
            else: s = 1
            k.append(bool(s))
        l[4] = k

解释：

data类型为List[List[str]]，对应[row]

即l对应row

l[0]对应'0', l[0] = int(l[0])转变成0

l[1]同理；

l[2]对应'NDP;LIBERAL;GREEN;CPC'，首先split(';')去掉；，会返回['NDP','LIBERAL','GREEN','CPC']即可

l[3]前面和l[2]一样，只不过要循环，将List里面的str变成int，即变成数组；

l[4]多少与l[3]类似，多了一个if...else换成bool