python openpyxl 设置表格列宽的自动适应_python-openpyxl-调整列宽siz
python-openpyxl-调整列宽siz我有以下脚本将CSV文件转换为XLSX文件,但我的列大小非常狭窄。 每次我必须用鼠标拖动它们以读取数据。 有人知道如何在openpyxl中设置列宽吗?这是我正在使用的代码。#!/usr/bin/python2.6import csvfrom openpyxl import Workbookfrom openpyxl.cell import get_co
python-openpyxl-调整列宽siz
我有以下脚本将CSV文件转换为XLSX文件,但我的列大小非常狭窄。 每次我必须用鼠标拖动它们以读取数据。 有人知道如何在openpyxl中设置列宽吗?
这是我正在使用的代码。
#!/usr/bin/python2.6
import csv
from openpyxl import Workbook
from openpyxl.cell import get_column_letter
f = open('users_info_cvs.txt', "rU")
csv.register_dialect('colons', delimiter=':')
reader = csv.reader(f, dialect='colons')
wb = Workbook()
dest_filename = r"account_info.xlsx"
ws = wb.worksheets[0]
ws.title = "Users Account Information"
for row_index, row in enumerate(reader):
for column_index, cell in enumerate(row):
column_letter = get_column_letter((column_index + 1))
ws.cell('%s%s'%(column_letter, (row_index + 1))).value = cell
wb.save(filename = dest_filename)
Satish asked 2020-02-04T17:57:32Z
9个解决方案
64 votes
您可以估计(或使用等宽字体)来实现。 假设数据是一个嵌套数组,例如[['a1','a2'],['b1','b2']]
我们可以获取每一列中的最大字符数。 然后设置宽度。 宽度正好是等宽字体的宽度(如果至少未更改其他样式)。 即使您使用可变宽度的字体,这也是一个不错的估计。 这不适用于公式。
column_widths = []
for row in data:
for i, cell in enumerate(row):
if len(column_widths) > i:
if len(cell) > column_widths[i]:
column_widths[i] = len(cell)
else:
column_widths += [len(cell)]
for i, column_width in enumerate(column_widths):
worksheet.column_dimensions[get_column_letter(i+1)].width = column_width
有点骇人听闻,但您的报告将更具可读性。
Bufke answered 2020-02-04T17:57:51Z
33 votes
我对Bufke答案的不同意见。 避免对数组进行一些分支,并忽略空单元格/列。
现在修复了非字符串单元格值。
ws = your current worksheet
dims = {}
for row in ws.rows:
for cell in row:
if cell.value:
dims[cell.column] = max((dims.get(cell.column, 0), len(str(cell.value))))
for col, value in dims.items():
ws.column_dimensions[col].width = value
velis answered 2020-02-04T17:58:15Z
29 votes
设置至少在openpyxl版本2.4.0中有效的所有列的宽度的更多pythonic方法:
for column_cells in worksheet.columns:
length = max(len(as_text(cell.value)) for cell in column_cells)
worksheet.column_dimensions[column_cells[0].column].width = length
as_text函数应该是将值转换为适当长度的字符串的东西,例如Python 3:
def as_text(value):
if value is None:
return ""
return str(value)
User3759685 answered 2020-02-04T17:58:40Z
6 votes
我的merged_cells有问题,并且autosize无法正常工作,如果您有同样的问题,则可以使用以下代码解决:
for col in worksheet.columns:
max_length = 0
column = col[0].column # Get the column name
for cell in col:
if cell.coordinate in worksheet.merged_cells: # not check merge_cells
continue
try: # Necessary to avoid error on empty cells
if len(str(cell.value)) > max_length:
max_length = len(cell.value)
except:
pass
adjusted_width = (max_length + 2) * 1.2
worksheet.column_dimensions[column].width = adjusted_width
Virako answered 2020-02-04T17:59:00Z
3 votes
上面接受的答案略有改进,我认为是更Python化的(寻求宽恕比寻求许可要好)
column_widths = []
for row in workSheet.iter_rows():
for i, cell in enumerate(row):
try:
column_widths[i] = max(column_widths[i], len(cell.value))
except IndexError:
column_widths.append(len(cell.value))
for i, column_width in enumerate(column_widths):
workSheet.column_dimensions[get_column_letter(i + 1)].width = column_width
shayst answered 2020-02-04T17:59:20Z
2 votes
这是我的版本,引用@Virako的代码段
def adjust_column_width_from_col(ws, min_row, min_col, max_col):
column_widths = []
for i, col in \
enumerate(
ws.iter_cols(min_col=min_col, max_col=max_col, min_row=min_row)
):
for cell in col:
value = cell.value
if value is not None:
if isinstance(value, str) is False:
value = str(value)
try:
column_widths[i] = max(column_widths[i], len(value))
except IndexError:
column_widths.append(len(value))
for i, width in enumerate(column_widths):
col_name = get_column_letter(min_col + i)
value = column_widths[i] + 2
ws.column_dimensions[col_name].width = value
以及使用方法如下
adjust_column_width_from_col(ws, 1,1, ws.max_column)
alones answered 2020-02-04T17:59:44Z
1 votes
以上所有答案均产生一个问题,即col [0] .column返回数字,而worksheet.column_dimensions [column]仅接受诸如'A','B','C'之类的字符代替列。 我已经修改了@Virako的代码,现在可以正常工作了。
import re
import openpyxl
..
for col in _ws.columns:
max_lenght = 0
print(col[0])
col_name = re.findall('\w\d', str(col[0]))
col_name = col_name[0]
col_name = re.findall('\w', str(col_name))[0]
print(col_name)
for cell in col:
try:
if len(str(cell.value)) > max_lenght:
max_lenght = len(cell.value)
except:
pass
adjusted_width = (max_lenght+2)
_ws.column_dimensions[col_name].width = adjusted_width
Ssubrat Rrudra answered 2020-02-04T18:00:05Z
1 votes
我们可以将数字转换为其ASCII值,并将其提供给column_dimension参数
import openpyxl as xl
work_book = xl.load_workbook('file_location')
sheet = work_book['Sheet1']
column_number = 2
column = str(chr(64 + column_number))
sheet.column_dimensions[column].width = 20
work_book.save('file_location')
Prashant Tiwari answered 2020-02-04T18:00:25Z
1 votes
当openpyxl更新时,我不得不更改以上答案的@ User3759685。 我遇到了错误。 @phihag也在评论中报告了这一点
for column_cells in ws.columns:
new_column_length = max(len(as_text(cell.value)) for cell in column_cells)
new_column_letter = (openpyxl.utils.get_column_letter(column_cells[0].column))
if new_column_length > 0:
ws.column_dimensions[new_column_letter].width = new_column_length + 1
Monte Jones answered 2020-02-04T18:00:45Z
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